Java Program to Find where the Ascending order breaks in the existed sequence

public class CheckAscList {
/**
* @Order checking
*/
public static void main(String[] args) {
int[] intArray = { 1, 3, 5, 6, 7, 8, 11, 13, 15, 4, 17, 19, 21, 23 };
for (int i = 0; i < intArray.length - 1; i++) {
if (intArray[i] > intArray[i + 1]) {
System.out
.println("Ascending order of the list breaks at index =>> "
+ (i + 1) + " and the element is =>> "
+ intArray[i + 1]);
}
}
}
}

OUTPUT1:

Ascending order of the list breaks at index =>> 9 and the element is =>> 4

2)To find where Descending order is breaking

public class CheckDscList {

/**

* @CheckDcsList

*/

public static void main(String[] args) {

int[] intArray = { 23,21,19,18,17,15,4,12,10,8,7,5,3,2 };

for (int i = 0; i < intArray.length - 1; i++) {

if (intArray[i] < intArray[i + 1]) {

System.out

.println("Descending order of the list breaks at index =>> "

+ (i) + " and the element is =>> "

+ intArray[i]);

}

}

}

}

OUTPUT2:

Descending order of the list breaks at index =>> 6 and the element is =>> 4